The Monty Hall Problem |
| Suppose you're on a game show and you're given the choice of three doors. Behind one door is the grand prize; behind the others, booby prizes. You pick a door, say Door 1, and the host, who knows what is behind each door, opens another door, say Door 2, revealing a booby prize. The host then offers you the opportunity to change your selection to Door 3. Should you stick with your original choice or switch? Does it make any difference? (This is similar to the routine on the TV game show Let's Make a Deal, hosted by Monty Hall, hence the name of the problem.) |
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| Assuming that the host always chooses to open a door with a booby prize,
and would never reveal the grand prize, the possibly surprising answer
is that you should switch to the third door, which is now twice as likely
as your original choice to be hiding the grand prize. When you chose Door
1, the probability that you chose the grand prize was 1/3 and the probability
that it was behind one of the other doors was 2/3. By showing you which
of Doors 2 and 3 does not hide the grand prize (Door 2, say), the host
is giving you quite a bit of information about those two doors. The probability
is still 2/3 that one of them hides the grand prize, but now you know which
of the two it would be: Door 3. So, the probability is still only 1/3 that
the grand prize is behind Door 1, but 2/3 that it is behind Door 3.
If you find this result counterintuitive (and even most mathematicians
do) and your browser is JAVA-capable, try the simulation below. Choose
a door by clicking on it. The host (your computer) will then open one of
the other doors, revealing a pig. You may then, by clicking on the appropriate
door, choose to stick with your choice or switch to the remaining door.
After a moment the doors will close to allow you to try again. Below the
doors are shown two running calculations: the experimental probability
that you will win if you stay with your original choice and the experimental
probability that you will win if you switch. After many tries, will these
numbers be close to 1/2, or will they be close to 1/3 and 2/3 respectively?
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Jill Britton Home Page applet and text by Steven R. Costenoble |
21-August-2007
Copyright Jill Britton |