We begin with a video approach
to Perigal's proof (courtesy of YouTube).
Click
on the size button (to the right of the volume button) for a full screen
view.
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And this approach utilizes an applet.
| Explanation:
Click on the Show names option above. Assume b > a, so that the lines parallel
and perpendicular to the hypotenuse of The length of both segments of these lines inside the square equal the length of the hypotenuse c. Each segment is divided by M into equal parts of length c/2. Drop a perpendicular from M onto CBc. Its foot will land in the middle of CBc. A triangle will be formed with the sides
parallel to those of The endpoints on the add-on lines in square ACBcBa divide its sides (each of length b) into two parts (a + b)/2 and (b - a)/2. Since we have the the emergence of a square of
side a after rearrangement of the pieces on the hypotenuse.
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| Applet copyright Interactive Mathematics Miscellany and Puzzles |